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5p^2+10p-400=0
a = 5; b = 10; c = -400;
Δ = b2-4ac
Δ = 102-4·5·(-400)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-90}{2*5}=\frac{-100}{10} =-10 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+90}{2*5}=\frac{80}{10} =8 $
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